phint_length() calculates the total length of all time spans within each
phinterval element in seconds. For phintervals with multiple disjoint spans,
the lengths are summed. Instantaneous intervals and holes have length 0.
phint_lengths() returns the individual length in seconds of each time span
within each phinterval element.
Usage
phint_length(phint)
# Default S3 method
phint_length(phint)
# S3 method for class 'Interval'
phint_length(phint)
# S3 method for class 'phinterval'
phint_length(phint)
phint_lengths(phint)
# Default S3 method
phint_lengths(phint)
# S3 method for class 'Interval'
phint_lengths(phint)
# S3 method for class 'phinterval'
phint_lengths(phint)Value
For phint_length(), a numeric vector the same length as phint.
For phint_lengths(), a list of numeric vectors the same length as phint.
Examples
monday <- interval(as.Date("2025-11-10"), as.Date("2025-11-11"))
friday <- interval(as.Date("2025-11-14"), as.Date("2025-11-15"))
phint_length(monday)
#> [1] 86400
phint_length(phint_intersect(monday, friday))
#> [1] 0
# phint_length() sums the lengths of disjoint time spans
mon_and_fri <- phint_union(monday, friday)
phint_length(mon_and_fri) == phint_length(monday) + phint_length(friday)
#> [1] TRUE
# phint_lengths() returns the length of each disjoint time span
phint_lengths(mon_and_fri)
#> [[1]]
#> [1] 86400 86400
#>